80=0.0865t^2

Solution for 80=0.0865t^2 equation:

80=0.0865t^2

We move all terms to the left:

80-(0.0865t^2)=0

We get rid of parentheses

-0.0865t^2+80=0

a = -0.0865; b = 0; c = +80;
Δ = b2-4ac
Δ = 02-4·(-0.0865)·80
Δ = 27.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{27.68}}{2*-0.0865}=\frac{0-\sqrt{27.68}}{-0.173}
=-\frac{\sqrt{}}{-0.173}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{27.68}}{2*-0.0865}=\frac{0+\sqrt{27.68}}{-0.173}
=\frac{\sqrt{}}{-0.173}
$